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Honors Hydrate worksheet #5-7
POSTED: 08/03/2017 at 4:25pm  BY: Cristina Welch Comments (0) Comment on Post

5) Answer:  CaSO4 2H2O

anhydrous moles = 13g / 136.15 = 0.10mol

water moles = 3.4 / 18/02 = 0.19 mol

X = 0.19/0.10 = 2

6) Answer: CoCl2 6H2O

anhydrous moles = 54.57g / 129.83g = 0.42 mol

water moles = 45.43g / 18.02g = 2.52 mol

X = 2.52/0.42 = 6

 


CP hydrate problem #181
POSTED: 08/03/2017 at 4:04pm  BY: Cristina Welch Comments (0) Comment on Post

pg 361 #181  BaCl2 XH2O

 

Step 1) mass of anhydrous = mass after heating - mass of crucible = 8.57g

            mass of water = (mass of hydrate + crucible) - mass after heating = 1.38g

 

Step 2) moles of anhydrous = mass of anhydrous/molar mass of anhydrous = 8.57g/208.23g = 0.04mol of anhydrous

            moles of water = mass of water/molar mass of water = 1.38g / 18.02 = 0.08mol of water

 

Step 3) Find X.  X = mol of water/mol of anhydrous = 0.08 mol water/ 0.04 mol of anhydrous = 2

Correct formula: BaCl2 2H2O


Honors hydrate book problems
POSTED: 07/03/2017 at 6:05pm  BY: Cristina Welch Comments (0) Comment on Post

Hydrate problems (end of chapter 10)

181)  BaCl2 (dot) 2H2O

182)   Cr(NO3)3 (dot) 9H2O

184)   BaCl2 (dot) 2H2O

185)  CaSO4 (dot) 2H2O

186) MgI2 (dot) 8H2O

187) Na2B4O7 (dot) 10H2O

 


CP Homework 2/15 block 6
POSTED: 27/02/2017 at 3:50pm  BY: Cristina Welch Comments (0) Comment on Post

Pg 444 questions 2-4.  Also complete 3 note cards (front and back).  One card for each gas law that we covered today.


Honors Homework: 2/27
POSTED: 27/02/2017 at 3:48pm  BY: Cristina Welch Comments (0) Comment on Post

Complete sections I and II on your study guide.  Answer these questions on no less than (3) note cards (front and back).



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